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-1.9x^2+12x-15.5=0
a = -1.9; b = 12; c = -15.5;
Δ = b2-4ac
Δ = 122-4·(-1.9)·(-15.5)
Δ = 26.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-\sqrt{26.2}}{2*-1.9}=\frac{-12-\sqrt{26.2}}{-3.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+\sqrt{26.2}}{2*-1.9}=\frac{-12+\sqrt{26.2}}{-3.8} $
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